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> I'm still not so sure about the odd away, even away business.
> ie 4-3 and 4-2 in a 5 pointer.
Ask yourself, "How many doubled games does my opponent need to win at this
match score?" You must assume that your opponent will always double
immediately.
If you are leading 1-away 3-away then your opponent needs to win two games:
one automatically doubled and then at 1-away 1-away. If, however, he
doubles and you drop, the score becomes 1-away 2-away. Your opponent now
only needs to win one automatically doubled. You have given away a whole
game!!
If you are leading 1-away 4-away then your opponent also needs to win two
games: both automatically doubled. If the first game starts off badly for
you, you can drop to 1-away 3-away and your opponent still has to win two
games as above. This is why the drop is "free"; you have lost a game but
your opponent still needs to win the same number.
LESSON: YOU ONLY HAVE A FREE DROP IF YOUR OPPONENT IS AN EVEN NUMBER OF
GAMES FROM WINNING.
Hope this helps. If not, sit down with a pencil and paper and mark off
imaginary results from 1-away 8-away until it clicks - that's what I had to
do!
ian
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