Forum Archive :
Opposing sums and differences
Jim Peplow wrote:
> While playing BG on the 'net, the exact pip count is always available.
> However, while playing "real world" games it's not so easy.
> What is the easiest way to get a pip count? I'm guessing it may have
> something to do with figuring an average for each quadrant of the board.
> Thanks for any input.
It is a tedious process when you start, but certain things that come
up frequently make it easier. 2 checkers "opposing" each other total
25. Bar and 8 point checkers total 15. The midpoint is 13 times
whatever difference in number of checkers there. I count the two
outfields and take the difference, and then add the two home boards.
Most of the time I get it right.
- Casting out crossovers (Mark Denihan, Oct 1996)
- Cluster counting (camelx+, May 2005)
- Counting half rolls (Bob Hoey, Apr 1998)
- Half-crossover method (Douglas Zare, Mar 2002)
- Live play versus online (Stanley E. Richards+, Apr 2006)
- Live play versus online (Rich+, Mar 2006)
- Mental shift (Stephen Turner, Oct 1996)
- Modified direct count (Daithi, Mar 2011)
- Opposing sums and differences (Donald Kahn, Apr 1998)
- Running pip count (Rodrigo Andrade+, Apr 1998)
- Symmetry method, Grouping men (Brian Sheppard, Jan 1997)
- The 51/21 count (kruidenbuiltje, Mar 2011)
- Tips (Patti Beadles, Dec 1994)
- Tips for counting pips (neilkaz, Sept 2010)
Backgammon Galore :
Forum Archive Main Page